QR: Rotational Inertia

Hi, I like to have this quiz question revisited! Please leave comments as to why the answer is B. In particular, could you please explain why the HS has a greater rotational inertia than the SC in this question? You should discuss qualitatively, but rigorously, without relying on the calculated values of rotational inertia.


OK, here is something. In the following proof, the parallel axis theorem is used implicitly when we conclude that IA > IB for each pair of pieces A, B means IHS > ISC. Here, A is an arbitrary piece out of all sliced pieces of a hollow sphere, and B is the corresponding sliced piece for the cylinder. That is r goes from 0 to R.